Write a C program to convert the digits into words

Input: 123 Output: one hundred twenty three

#include 
#include 
#include 
void main(){
    char init[27][12] = {" one "," two "," three ",
                " four "," five "," six ",
                " seven "," eight "," nine ",
                " ten "," eleven "," twelve ",
                " thirteen "," fourteen "," fifteen ",
                " sixteen "," seventeen "," eighteen ",
                " nineteen "," twenty "," thirty ",
                " fourty "," fifty "," sixty ",
                " seventy "," eight "," ninty "};
    char sthou[20]="",shund[20]="",sval1[20]="",sval2[20]="",result[100]="";
    int thou=0,hund=0,ten=0,temp=0,val1,val2,num,rem,c=0;

clrscr();
//USING COBOL LOGIC
     printf("*****AMOUNT IN WORDS*****\n\n");
     printf("Enter any value (upto 4 digits) : ");
     scanf("%d",&num);
     while(num>0){
         rem = num%10;
         c++;
         if(c<=2)
        temp = temp * 10  +rem;
         elseif(c==3)
        hund = rem;
         elseif(c==4)
        thou = rem;
         num = num/10;
     }
     while(temp>0){  //as ten contains two digit so reverse it
        rem = temp%10;
        ten = ten * 10 + rem;
        temp= temp/10;
     }

     if(thou>0){
       strcpy(sthou,init[thou-1]);
       strcat(sthou," thousand ");
       strcat(result,sthou);
     }

     if(hund>0){
       strcpy(shund,init[hund-1]);
       strcat(shund," hundred ");
       strcat(result,shund);
     }

     if(ten>0){
          if(ten>20){
          val1 = ten/10;
          val2 = ten%10;
          }
          if(val1>0){
           strcpy(sval1,init[val1+(18-1)]);
           strcat(result,sval1);
          }
          if(val2>0){
           strcpy(sval2,init[val2-1]);
           strcat(result,sval2);
          }
     }
     printf("\n\nAmount in word is as under \n");
     printf("%s",result);

getch();
}